BlueViolince Posted December 14, 2014 Share Posted December 14, 2014 I'm thinking of turning my old crybaby into a dual expression for my hd500 and m5. It's hard to find any properly sized dual 10k linear pots. Found a few 100k and up. Could I wire resistors/pots in parallel with the main expression pots to get a 10k value, and still get a linear sweep? I did it with a 100k log pot before, but the taper was awful. Not sure if it would work the way I want it to with linear pots. Quote Link to comment Share on other sites More sharing options...
pfsmith0 Posted December 15, 2014 Share Posted December 15, 2014 No, you won't get a linear sweep with a resistor/pot combo. The only way I can think to get a linear sweep is to hook ten 100k pots in parallel, which isn't a very good solution. Have you tried Digikey or Mouser? Would this work? http://www.mouser.com/ProductDetail/Alpha-Taiwan/RV24BF-10-15R1-B10K/?qs=sGAEpiMZZMtC25l1F4XBU1WTGPRHe%252bkusTraLEPePy0%3d Quote Link to comment Share on other sites More sharing options...
BlueViolince Posted December 15, 2014 Author Share Posted December 15, 2014 How about just wiring nine 100k resistors in parallel with the pot? I don't know the theory behind this, so I'm throwing out guesses here. Quote Link to comment Share on other sites More sharing options...
BlueViolince Posted December 15, 2014 Author Share Posted December 15, 2014 never mind, that doesn't make sense. Quote Link to comment Share on other sites More sharing options...
pfsmith0 Posted December 15, 2014 Share Posted December 15, 2014 That will certainly go from 10k to 0 like you want, but it won't be even close to linear Quote Link to comment Share on other sites More sharing options...
BlueViolince Posted December 16, 2014 Author Share Posted December 16, 2014 I think the one you linked might work. the shaft is super short, but the distance between pot and the rack is really close in this enclosure. Quote Link to comment Share on other sites More sharing options...
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