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I think I know the answer to this, as it makes sense, but I just want to confirm.  I have two L3s and two L3t, I was using the M20d but I am switching to another mixer.  In the L3 diagrams in the user guide it shows going L and R out of a non M20d mixing board into the first L3s L and R inputs then daisy chaining the rest via Line 6 Link.   So I am assuming that I could also go L to one L3s and R to the other and then just use the L6 Link to go from each L3s to the L3t sitting on top of it.  Is anyone running this way?

 

 

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Hmmm... interesting question. I don't have two L3s; I run M20d and L6 Link to one L3s and two L3t. So I can't test this but I'm not sure I agree with your theoretical assumption.

 

Each L3s/t combination is receiving one half of a stereo signal but of course can't 'know' that. If the signals are summed to mono on each side (is that even meaningful?), either within the L3s or the L3t via L6 Link, is that identical to having each signal treated as half a stereo pair? I'm not 100% sure that the stereo panning in the mixer will translate properly. I confess I'm confused and will have to think further on this.

 

Is there any advantage to not sending both L+R to one L3s and using the L6 Link daisy chain as recommended? I think the only setup difference would be that the recommended setup requires one additional L6 Link (AES/EBU) cable. Is that the motivation or am I missing something?

 

Edit: After thinking a bit more I don't think it makes sense that the L3s could sum the incoming signal to mono because it already is mono as far as the L3s is concerned. But what will L6 Link do with it? How will the L3t interpret the signal it receives - the identical signal that the L3s received (adjusted for crossover) or 'half' of it (whatever that means)?

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I have enough AES/EBU cables the motivation is really just about convenience.  I'm not sure I am understanding the pitfalls you are suggesting with my proposed setup.  Maybe a better explanation will help.  So I will try to explain my logic.

 

Based on the fact that with a traditional mixer Line 6 is suggesting that I run L from the mixer to L into the L3s and the same for the R signal.  Then daisy chain the line 6 link.  It makes sense to me that once the L3s receives these two audio signals from the mixer it is able to pass them on via L6 link and separate them into L and R keeping the L for itself and the first L3t in the chain and pass the audio from R side onto the next two speakers in the chain.

 

So I am theorizing that if it can do this, I should be able to send only the L signal from the L out of the board to one L3s and this would be the only signal it could pass on to the L3t that is connected to it via L6 link.  The same on the right side it is getting only the R signal from the board and only has to pass this on to the connected L3t.  The only task that the L6 Link protocol has to do other than pass on the audio signal is determine the crossover point, which it also has to do in the other scenario.  The L3s no longer has to determine L and R, it just takes the only signal it receives, L or R, keeps all the frequencies below the crossover point for itself and passes on the rest of the frequencies above that point to the L3t.

 

Does this make more sense than my original point?  or do you still foresee an issue?

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Yes I think you're right. That's a clear explanation of what my muddled brain was struggling with. I think the potential issue I tried to describe was mostly in my mind. Somehow I was thinking that stereo separation might be an issue but now I agree with you.

 

Let us know how it goes.

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