Sorry but you are most definatley Wrong.
For two resistances in parallel the total can never be greater than the lowest resistance in the pair.
The formula for two resistances in parallel is
R1 X R2
R1 + R2
It's not 12ohms and can't possibly be more than 8 ohms. It's 5.333 ohms for each channel with the two speakers in parallel an 8 and a 16.
Do it yourself.http://www.sengpiela...paralresist.htm
Just plug 8 into one slot and 16 in the other and hit calculate.
You can also do it with this formula
1/RT = 1/R1 + 1/R2 + 1/R3 = 1/R4 and so on depending on how many resistors you have in parallel
but the answer will be the same.
I wasn't an EE for over 40 years for nutin. This is really simple, I used have to do this sort of thing and much more with sliderules. You have it easy these days. LOL
Thanks for your reply..
anyway, the parallel combination of internal and external would be 16 // 8 = 12 ohms and not 5.33 ohms for each channel in normal mode.... I think this is the best configuration if I want to use all 4 speakers