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WalterJinkens

Watts drawn from Hd500x with jtv59 being powered by it.

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Hello I am wondering how to figure out or if anyone knows the watts used from the HD500x by itself and with the JTV-59 being powered by it?

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The number of watts is equal to amps multiplied by volts.  The HD500x requires a 3 amp by 9 volt power supply.  3x9=18 watts.

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1 hour ago, joel_brown said:

The number of watts is equal to amps multiplied by volts.  The HD500x requires a 3 amp by 9 volt power supply.  3x9=18 watts.

 

How many hamster wheels running full-tilt would I need to crank out those 18W? ;)

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What I know is that the current drain of a Variax is around 500 mA

 

..and I guess that around 2 A would suffice for the POD alone (not powering the Variax)

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Thanks! So I was looking at getting a power bank and wanted to make sure a 50 or 100 watt would be efficient enough. I play4 hour gigs sometimes so need something that'll run at least that long.

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To understand which type of power pack might be good for your needs you should think in terms of its capacity, ie in Ah (amp hours) or Wh (watt hours).

Therefore, knowing that the POD to work properly needs 9v of voltage and 3A of available current (if the Variax is powered by the POD), you must calculate how many Ah of capacity must be able to supply the power pack to cover the necessary operating time before current drops below the necessary level.

 

The following video clip could help to do your math:

 

 

 

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All about POD HD500/X

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