Question on 4 CM method

[fenderbenderlax]

hi Folks,

 

I use my hx fx with the four cable method currently. The set up is 

 

Guitar -> HX input

Send 1 -> Amp in

Amp send -> HX return 1

HX Left mono out -> Amp Return

 

HX right out -> Audio interface

 

I'm also running a split at the end of the chain (Y split) and adding a second path with an IR in there. At the merge point I'm panning the signal hard left (to amp) and hard right (to audio interface). 

 

This allows me to use an IR along with my amp. However, I'm looking into the possibility of using two IR's instead of 1 in parallel. The idea would be to take out the HX Left mono out to the amp return cable and instead send that to the audio interface with a second IR in that path. 

 

Would that work? I have an internal load on my amp so running without a speaker is fine. I guess my big question is if we do not send the mono out to the return, is the power amp captured in the chain? Maybe I'm completely out of whack here but any insight is much appreciated. 

 

My guess is that I could do something like this, 

 

Guitar -> HX input

Send 1 -> Amp in

Amp send -> HX return 1

Send 2 -> Amp Return

Amp Line out -> Return 2

 

Place the two IR's after the second FX loop block and run the Left and Right out to my interface. 

 

However this would mean using 4 blocks effectively for the FX loops and the IR's leaving just four blocks for effects I guess. Is there a simpler routing to get to this point? 

 

 

Thanks

 

[rd2rk]

50 minutes ago, fenderbenderlax said:

I guess my big question is if we do not send the mono out to the return, is the power amp captured in the chain?

 

Unless the amp is designed with a built-in load box (Suhr has one of these), the only way to get the PowerAmp into the signal chain is with an external Reactive Load box (Suhr has one of these too), taking the Line Out from the load box back to a Helix Return.